need help how to transpose equation

[zmoktyok]

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ari lang ni naku e post ha, guys tabangi intawn ko ani
need to get the weight, 0.2539=SQRT{(4 * WEIGHT) / (8.89 * 3.14159)}

[malcolm]

Weight=0.4502 i think. hehe...

[geo25]

PEMDAS

Ma-multiply na man nimo ang (8.89 * 3.14159) -> 27.9287351

0.2539=SQRT ( (4 * WEIGHT) / 27.9287351 )

Opposite of square root is a square, so square both sides to eliminate the square root symbol

( 0.2539 )^2 = ( SQRT(4*WEIGHT) / 27.9287351 )^2

^2 cancels SQRT

4 weight = 0.06446521
----------
27.9287351

Multiply both sides -> 27.9287351

4 Weight = 0.06446521 * 27.9287351

Divide both side by 4

Weight = (0.06446521 * 27.9287351 ) / 4

[zmoktyok]

korek! salamat

Weight=0.4502 i think. hehe...

[zmoktyok]

salamat kaayu!

PEMDAS

Ma-multiply na man nimo ang (8.89 * 3.14159) -> 27.9287351

0.2539=SQRT ( (4 * WEIGHT) / 27.9287351 )

Opposite of square root is a square, so square both sides to eliminate the square root symbol

( 0.2539 )^2 = ( SQRT(4*WEIGHT) / 27.9287351 )^2

^2 cancels SQRT

4 weight = 0.06446521
----------
27.9287351

Multiply both sides -> 27.9287351

4 Weight = 0.06446521 * 27.9287351

Divide both side by 4

Weight = (0.06446521 * 27.9287351 ) / 4

[spectrespook]

Assignment siguro ni ninyo TS?

[prukutung]

pde sad ka mag shift solve ani

[borrise]

0.2539=sqrt{(4 * weight) / (8.89 * 3.14159)}


weight = {[(0.2539)^2]*[8.89*3.14159]}/4