try VB sa fibo series... lingaw au
Iterative Solution with only three variables used.
Code:#include <stdio.h> #include <conio.h> void main() { int x, a, b; clrscr(); a = 1; b = 0; printf("How many Fibonacci numbers to display? : "); scanf("%i",&x); printf("Displaying [%i] Fibonacci Numbers:\n",x); while(x<=1){ a = a + b; b = a - b; printf("[%5i]", b); x--; } getch(); }
Last edited by ChaosOrb; 07-02-2009 at 11:10 AM. Reason: added variable x in 2nd printf
void fibo(int x, int y, int iter)
{
int temp;}
if (iter)
{
printf("%d ", x);}
temp = y;
y += x;
x = temp;
iter--;
else
return;fibo(x, y, iter);
int main(int argc, char* argv[])
{
int iter;}
printf("Enter iterations: ");
scanf("%d", &iter);
printf("Fibonacci sequence [%d]: ", iter);
fibo(0, 1, iter+1);
printf("\n");
return 0;
hi guys new po me dito try this code for generating fibonacci series
hope this code may help you!!!! ^__________________________^
#include <stdio.h>
#include <conio.h>
main(){
int num,x,row,res,num1;
clrscr();
row=1;
num=1;
x=0;
printf("Enter Number To Generate Fibonacci Series: ");
scanf("%d",&num1);
while (row<=num1){
res=num+x;
num=x;
x=res;
printf("%d ",res);
row=row+1;
}
getch();
}
hahah! i cn stll rmmbr during college we ussually ask help here^^
daghana answer oh..papili-ah imo teacher assa ana . haha
Unsay usbon ani
para ang result kay 1 1 2 4 7
#include<stdio.h>
int main()
{
float a,maxn,b,c,d;
printf("Enter maximumn number of values in series \n");
scanf("%f",&maxn);
a=;b=;
printf("\n\n") ;
printf("%1.0f\n",a);
printf("%1.0f\n",a);
for(d=1;d<=maxn-2;d++)
{
c=a+b;
b=a;
a=c;
printf("%1.0f\n",c) ;
}
getch();
}
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