Algebra Problem/Assignment

[cebu.opportunities]

---

naa koy mura'g solution sa second problem, di ko sure kun sakto ba. maulaw ta ko magpost kay basig sayup...hehehe dugaydugay na ko nag-algebra 8th grade paman seguro to... but maybe naay math expert diri, pakicheck nalang... nalingaw bya ko bisan di ko math person, but i do think math is fun, sometimes

3x - 5z = 1
2x + 3y = 6
x + y + z = 5

3 0 -5 1
2 3 0 6
1 1 1 5

3 0 -5 1
0 1 -2 -4
1 1 1 5

1 0 -5/3 1/3
0 1 -2 -4
1 1 1 5

1 0 -5/3 1/3
0 1 -2 -4
0 1 8/3 14/3

1 0 -5/3 1/3
0 1 -2 -4
0 0 14/3 26/3

1 0 -5/3 1/3
0 1 -2 -4
0 0 14 26

1 0 -5/3 1/3
0 1 0 -2/7
0 0 14 26

1 0 -5/3 1/3
0 1 0 -2/7
0 0 1 13/7

therefore, x = 1/3 + (5/3)z
y = -2/7
z = 13/7

sakto imong answer. ing.anion diay nang matrices.

analyzon niya ni nako kung wai lingaw.

ang first problem, di jud masakto ang first equation so sakto pud tingali ka nga there's no solution.

[superidol]

scared q ani . . kay take 2 jd ni naq nga subject. .

[cebu.opportunities]

naa untay maka explain ani. giunsa mani, hehe. puro number rmn gud ako makita.

naa koy mura'g solution sa second problem, di ko sure kun sakto ba. maulaw ta ko magpost kay basig sayup...hehehe dugaydugay na ko nag-algebra 8th grade paman seguro to... but maybe naay math expert diri, pakicheck nalang... nalingaw bya ko bisan di ko math person, but i do think math is fun, sometimes

3x - 5z = 1
2x + 3y = 6
x + y + z = 5

3 0 -5 1 <---- I understand
2 3 0 6 <---- understandable
1 1 1 5 <------- clear enough

3 0 -5 1 <----- retain/ as is
0 1 -2 -4 <------ I didn't get it.
1 1 1 5 <------retain/ as is

1 0 -5/3 1/3 <------ I get it
0 1 -2 -4 <--------- retain/ as is
1 1 1 5 <----------- retain/ as is

1 0 -5/3 1/3 <------- retain/ as is
0 1 -2 -4 <--------- retain/ as is
0 1 8/3 14/3 <------- eliminate "x" (convert to fraction with denominator of 3 then subtracted by first equation?)

1 0 -5/3 1/3 <----- retain/ as is
0 1 -2 -4 <------- retain/ as s
0 0 14/3 26/3 <-----

1 0 -5/3 1/3 <---------- as is
0 1 -2 -4 <--------- as is
0 0 14 26 <---------- multiply both sides with 3

1 0 -5/3 1/3 <------as is
0 1 0 -2/7 <------ (divide both sides with 2 so----> "0 1 0 -2" then divided by 7 of "z" (2*7) <-----not sure
0 0 14 26 <-------- as is

1 0 -5/3 1/3 <-------- as is (answer)
0 1 0 -2/7 <------- as is (answer)
0 0 1 13/7 <-------divide both sides with 14 so -----> 0 0 1 26/14, then reduce using the factor of 2 so ------> 0 0 1 13/7

therefore, x = 1/3 + (5/3)z
y = -2/7
z = 13/7