Set of Operation-Union in Java

[intheb0x]

---

mga istoryans please mangau ko ninyo idea bahin ani kay ang akong code dli man mogana mao ni ako code

public static void Union(char seta[], char setb[], char setc[], int n1, int n2, int n3)
		{
			int x, y;
			char a=0,b=0,c=0;
			System.out.print("\nUnion: ");
			for(x=0;x<n1;x++)
				{
					for(y=0;y<n2;x++)
						{
							if(y<1)
								{
									if(seta[x]==setb[y])
										{
											a=seta[x];
											System.out.print(seta[x]);
										}
									else
										{
										a=seta[x];
										b=setb[y];
										System.out.print(seta[x]);
										System.out.print(seta[y]);
										}
								}
							else if (y==1)
								{
									if((seta[y]==a)||(setb[y]==b))
										continue;
									else
										c=setb[y];
										System.out.print(setb[y]);
								}
							else if(y>1)
								{
									if(((setb[y]==a)||(setb[y]==b)||(setb[y]==c))&&((setb[y]==a)||(setb[y]==b)||(setb[y]==c)))
										continue;
									else
										System.out.print(setb[y]);
													}

					}
				}


		}

wala na lang ko gamit java.util.Set kay wla pa man namo na discuss...

[intheb0x]

btw unsaon pag store sa usa ka char sa array? like

for(x=0;x<n1;x++)
	{
		for(y=0;y<n2;x++)
		{
                        if(seta[x]==setb[y])
                     -- store seta[x] in a third array--
}
}

[stealthghost]

regular array,

String[] array = {"array1", "array2"};

or

String[] array = new String[2];
//Do some loops if you want;
array[0] = "array1";
array[1] = "array2";

bali imuha, I think..

in your code, a=seta[x];

dapat seta[x] = a;