help plss for my assignment

[kronouzgg]

---

mga kua's pa help nmn ko ani nag lisud jud ko ani.. kani ang ako problem

group 1 males under 25 years old
group 2 females "' " " "
group 3 males between 25-45" "
group 4 females " "
group 5 all people are 45years old

design a program to input a necessry information for a person and output his/her group

#include<stdio.h>void main ()
{
int AGE;
char G;
printf("\n\nGender Male [M/m] - Female [F/f]: ");
scanf("%s",&G);
printf("\n\nAge: ");
scanf("%d",&AGE);
if ((G=='M' || G=='m') || (G=='F' || G=='f') )
if(AGE<25)

printf("\n\n\nGroup 1\n\n\n");
else if( G=='F' || G=='f')
printf("\n\n\nGroup 2\n\n\n");


else
if ((G=='M' || G=='m') || (G=='F' || G=='f') )
if(25>45)
printf("\n\n\nGroup 3\n\n\n");
else
if( G=='F' || G=='f')

printf("\n\n\nGroup 4\n\n\n");

}

mao na ako gi code murag sayup man kay inig input nako sa f dili siya mo group 2 hahaiz tabang plss

[carmicael]

naay something wrong sa imong condition.
use braces para ma group ug tarong imong conditions, para di ka mag libog.

refer to this segment:

if ((G=='M' || G=='m') || (G=='F' || G=='f') )
    if(AGE<25) 
        printf("\n\n\nGroup 1\n\n\n");
    else if( G=='F' || G=='f') 
        printf("\n\n\nGroup 2\n\n\n");

*if musulod siya sa first condition, then no sense na mag "else if" pa ka ug (G=='F'....
*ang expected output ani imong gi-provide na code kay:
-> m, < 25 : "Group 1" is printed
-> m, 25 + : nothing happens
-> f, < 25 : "Group 1" is printed
-> f, 25 + : "Group 2" is printed

[kronouzgg]

lagi mao nay mugawas ganiha ra jud ko gahunahuna unsaon . ahm give me more some idea plss

[muchacha00]

kid... sunod bah paminaw sa imong maestro then if lisoran ka do a research .... and ask MR. google.. unsay gamit sa internet......

[carmicael]

lagi mao nay mugawas ganiha ra jud ko gahunahuna unsaon . ahm give me more some idea plss

naa kay 4 ka categories, therefore, at most, 4 ka conditions ang imo kelangan. naa kay Male, less than 25yo; Male, 25yo or older; Female, less than 25yo; Female, 25yo or older. mao na ang imong 4 conditions.

if(Male and less than 25yo)
   do something 1
else if(Male and 25yo or older)
   do something 2
else if(Female and less than 25yo)
   do something 3
else
   do something 4

you need not complicate things further like sa imong code, na daghan pa kaayo nested if-conditions.

naa diay cheat code, pero ayaw basaha until wa pa ka naka solve sa imong problem. (temptations...)

Spoiler! 

ayaw sa lage.

[kronouzgg]

sige idol wla pa nako gi ablihan.. ako sa ni e solve di ko mag salig sa cheat .. gusto jud ko makat on og mayo .. kya need sad nako og idea ninyo kay di man nako makaya

[carmicael]

mao na to ang kina simple na solution. 4 ka conditions. ang pseudocode sa ako previous post, i-convert to C. mao na to ang hint. unsa na hint pa imo gipangita?

[kronouzgg]

idol mao na ni nakuha na ba nako? pls inform me kung sakto na

#include<stdio.h>
void main ()
{
int AGE;
char G;
printf("\n\nGender Male [M/m] - Female [F/f]: ");
scanf("%s",&G);
printf(\n\nAge: ");
scanf("%d",&AGE);
if ((G=='M' || G=='m') && (AGE<25))

printf("\n\n\nGroup 1\n\n\n");
else
if((G=='F' || G=='f') && (AGE<25) )
printf("\n\n\nGroup 2\n\n\n");

else if((G=='M' || G=='m') && (25<45))

printf("\n\n\nGroup 3\n\n\n");

else if((G=='F' || G=='f') && (25<45))
printf("\n\n\nGroup 4\n\n\n");

}

[carmicael]

idol mao na ni nakuha na ba nako? pls inform me kung sakto na

medyo ok na ang hitsura, pero sayop imong duha ka last conditions. always mu true ang result sa "(25 < 45)" ang dapat ana kay "(AGE>=25)".

kani pod:

printf(\n\nAge: ");

kulang opening quotation marks.

---

anyway, congratulations. ok na imong program.
as promised, mao ni akong solution:

Spoiler! 

#include <stdio.h>

void main(void) {
    int AGE;
    char G;

    printf("\n\nGender Male [M/m] - Female [F/f]: ");
    scanf("%s", &G);
	
    if(toupper(G) != 77 && toupper(G) != 70)
        return;

    printf("\n\nAge: ");
    scanf("%d", &AGE);
	
    if(AGE < 0)
        return;

    printf("\n\n\nGroup %d\n\n\n", (((AGE < 25) ? 1 : 5) + 
	    (((toupper(G)) == 77) ? 1 : 3)) / 2);
}

[kronouzgg]

yes kuha na jud nako tanan bali master mao nani ang ako final answer ,, lisuda sabtun sa imoha code wew advanced kayo .. di ko kasabut ako sad gi try di siya mu run .. pero thanks kayo master sa idea

#include<stdio.h>
void main ()
{
int AGE;
char G;
printf("\n\nGender Male [M/m] - Female [F/f]: ");
scanf("%s",&G);
printf("\n\nAge: ");
scanf("%d",&AGE);
if ((G=='M' || G=='m') && (AGE<25))

printf("\n\n\nGroup 1\n\n\n");
else if((G=='F' || G=='f') && (AGE<25) )
printf("\n\n\nGroup 2\n\n\n");

else if((G=='M' || G=='m') && (AGE<=45))

printf("\n\n\nGroup 3\n\n\n");

else if((G=='F' || G=='f') && (AGE<=45))
printf("\n\n\nGroup 4\n\n\n");

else if((G=='F' || G=='f') && (AGE>45))
printf("\n\n\nGroup 5\n\n");
else if((G=='M' || G=='m') && (AGE>45))
printf("\n\n\nGroup 5\n\n");

}